Quote:
Originally Posted by jmoore
...
You start with 3.9% active ingredient, which is equal to 39 g / l (grams per litre) stock solution.
You need 350 micromoles in your final solution or 0.05 g / l ( based on the relative molecular mass you supplied of 144.something)
To reach that figure you divide your final mass of 0.05 grams ( as we are talking about 1 litre) by your starting concentration of 39 g / l which gives a figure of 1.28 ml / litre.
...
|
Correct. You win this weeks proportionality quiz!